13122=2/3*3^(3x+12)

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Solution for 13122=2/3*3^(3x+12) equation: 



13122=2/3*3^(3x+12)

We move all terms to the left:

13122-(2/3*3^(3x+12))=0



Domain of the equation: 3*3^(3x+12))!=0

x∈R



We multiply all the terms by the denominator


-(2+13122*3*3^(3x+12))=0



We calculate terms in parentheses: -(2+13122*3*3^(3x+12)), so:

2+13122*3*3^(3x+12)

determiningTheFunctionDomain
13122*3*3^(3x+12)+2

Wy multiply elements

118098x*3+2

Wy multiply elements

354294x+2

Back to the equation:

-(354294x+2)



We get rid of parentheses

-354294x-2=0

We move all terms containing x to the left, all other terms to the right

-354294x=2

x=2/-354294

x=-1/177147

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